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3x^2-6x=504
We move all terms to the left:
3x^2-6x-(504)=0
a = 3; b = -6; c = -504;
Δ = b2-4ac
Δ = -62-4·3·(-504)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-78}{2*3}=\frac{-72}{6} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+78}{2*3}=\frac{84}{6} =14 $
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